Question

A particle is drop from a tower. It covers 45m in last second of its journey. Find the hieght of tower

Answer 1

Answer:

The height of tower=101.25 m

Answer 2

Answer:

103.31 is the height if the tower

Explanation:

Given it covered 45m in last second. Hence final velocity 'v'= 45m/sec

It is dropped from certain height 's' its initial velocity 'u' = 0

a=9.8m/sec^2

we know

${v}^{2} - {u}^{2} = 2as$

${45}^{2} - {0}^{2} = 2 \times 9.8 \times s$

from this we get height 's' =2025/19.6 = 103.31 meters is the height of the tower.

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