A particle is dropped from a height H. The de Broglie wavelength of the particle as a function of height is proportional to: a. H b. H 1/2 c. H 0 d. H -1/2
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energy of particle at H height(E)=mgH
now
according to De-broglie concept,
lemda=h/mv=h/root {2mE}
put E value from above
lemda =h/root {2m^2gH}
hence we see wavelength is inversely proportional to square root of H
hence option (d) is correct .
now
according to De-broglie concept,
lemda=h/mv=h/root {2mE}
put E value from above
lemda =h/root {2m^2gH}
hence we see wavelength is inversely proportional to square root of H
hence option (d) is correct .
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