Question

a particle is dropped from a tower 180m heigh.how long does it take to reach the ground? what is the velocity when it touches the ground ? take g=10m/s2
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Answer 1

Answer:

By energy conservative

time = √(2gh) = √(2×10×180) = 60 seconds

v = u + gt = 0 + 10 ×60 = 600 m/s

Answer 2

Answer:

Given ,

u = 0

S = h = 180 m

a = g = 10 m/s²

v² = 0 + 2×10×180

   = 3600

v = √3600

  = 60 m/s

time taken to reach is given as ,

t = v-u / g

 = 60 / 10

 = 6 sec

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