A particle is dropped from a tower in a uniform gravitational field at t = 0. The particle is blown over by a
horizontal wind with constant velocity. Slope (m) of trajectory of the particle with the horizontal and its KE vary according to curves. (Horizontal velocity of particle is equal to wind velocity)
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Answers
Answer:
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Answer:
Explanation:
The vertical displacement towards ground is s
y
=
2
1
gt
2
The Horizontal displacement s
x
=vt
s=
s
x
2
+s
y
2
Replacing t=
v
s
x
s
x
=x
ds
x
ds
y
=
v
2
1
s
x
dx
d(h−y)
=
v
2
1
x
dx
dy
=−
v
2
1
x where h is the height of the tower and y is the height from the ground.
∴ slope =
dx
dy
∝−x