Question

A particle is dropped from a tower.it is found that it travels 55m in last second of the journey.then height of tower is.(g=10m/s^2)

Answer 1

Step-by-step explanation:

let the total time of journey be n seconds.

Distance traveled in nth seconds;

sn=u+a/2(2n-1)

=>45=0+10/2(2n-1)

n=5 sec

Height of the tower ;h=1/2gt²=1/2×10×5²=125m