Question

A particle is dropped from a tower. It is found that it travels 45 m in the last second of its journey. Find out the height of the tower? (take g = 10 m/s^2)

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Answer 1

hey mate!

Distance travelled in last second

S = u + a(n - 1/2)

45 = 0 + 10(n - 1/2)

n = 4.5 + 0.5

n = 5th second

Total time of flight is 5 seconds

Height of the tower

H = 0.5gt^2

= 0.5 × 10 × 5^2

= 125 m

Height of the tower is 125 m

Answer 2

THANKS FOR YOUR QUESTION

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