Question

A particle is dropped from height h. another particle which is initially at a horizontal distance d from the first is simultaneously projected with a horizontal velocity u and the two particles just collide on the ground then
1) d^2=u^2h/g 2) d^2=2u^2h/g 3) d=h 4) gd^2=u^2h

Answer 1

Answer:

Option C

D=H

Hope u understand

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