Question

A particle is dropped from height h.It strikes
at ground after 5 s. What is value of h? (Given
g=10 ms-2)​

Answer 1

Answer:

Explanation:

First body initial speed u=0

Final speed =3m/s

Second body initial speed=4m/s

Body is dropped from height h

So a=g=10m/s  

2

 

v  

2

=u  

2

+2gh

3  

2

=0+20h  

9=20h

h=  

20

9

​  

 

Second object is also dropped from same height.

therefore, h=  

9

20

​  

 

u=4m/s

v  

2

=u  

2

+2gh

v=5m/s

Answer 2

The value of h is 125 meters.

Given :

Time at which particle strikes at the ground - 5sec

Acceleration due to gravity - 10 ms^-2

To find:

Value of height, h

Solution:

We can simply solve the above problem as under.

we know,

initial velocity of the particle, u = 0 m/s

Time taken by the particle, t = 5sec

Acceleration due to gravity = 10m/s^2

Using the equation of motion,

$s = ut + \frac{1}{2} a {t}^{2}$

putting the values in the above equation we have,

$h = 0 \times 5 + \frac{1}{2} \times 10 \times 5 \times 5$

h = 125

height = 125 meters

The value of h is 125 meters.

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