A particle is dropped from the top a tower of height 4.9 M the velocity of the particle with which districts the ground is
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square (v) = square (u) + 2as
= 0 + 2(9.8*4.9)
= 48.02*2
= 96.04 m/s
hence velocity must be 96.04m/s
= 0 + 2(9.8*4.9)
= 48.02*2
= 96.04 m/s
hence velocity must be 96.04m/s
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