Question

A particle is dropped from the top of a 80m high tower. Taking g=10m/s² Determine:. (1): speed when it is at height of 60m. (2): Its height when it has fallen for 4 seconds.​

Answer 1

Answer:

1. 20 m/s

2. 0 m (on the ground)

Explanation:

h = 80m

g = 10m/s^2

u = 0 m/s

t = 4s

1. For s= 80-60=20m,

2as = v^2 - u^2

---> 2 × 10 × 20 = v^2 - 0^2

---> 400 = v^2

---> v = 20 m/s

2. Let h= 80 - s

s = ut + 1/2(at^2)

---> 80 - s = 1/2 × 10 × 4^2

---> s = 80 - 80

---> s = 0m

Therefore the particle is on the ground.

Answer 2

I hope it will help you

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