Question

a particle is dropped from the top of a high building of height 360m . The distance traveled by the particle in ninth second is (g= 10m/s²)​

Answer 1

Answer:

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Explanation:

Snth=u+1/2a(2n-1)

S9=0+1/2*10(2*9-1)

   =5(17)

   =85m

Verification:-Speed at 9th second=90m/s=v

Speed at 8th second=80m/s=u

v^2=u^2+2as

8100-6400=20s

1700/20=s

85m=s

Hope this helps you:)