Question

A particle is dropped from the top of a tower its covers 40m in last 2s. find the height of the tower

Answer 1

anwer is 45m,.......

Answer 2

H =ut + 1/2 gt^2
40 = u × 2 + 1/2 × 10 × 4
40 = 2u + 20
u = 10
Since partice has been dropped its initial velocity will be zero

v^2 = u^2 + 2gs
100 = 2*10*s
S=5
Height = 40 + 5 = 45 m