Question

A particle is dropped from the top of a tower of height 80 m. Find the time of jurney and the speed with which it strikes the ground.

Answer 1

Answer:

4seconds

hence proved...........

Answer 2

Answer:

s= 80m

u= 0m/s

t= ?

a= -g

v=?

Explanation:

$s = ut +1/2 a {t}^{2 } \\ - 80 = 0 -1/2g {t }^{2} \\ t = \sqrt{ \frac{160}{10} } = \sqrt{16} = 4 sec \\ \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 10 \times 80 } \\ v = \sqrt{1600} \\ v = 40m {s}^{ - 1}$