Question

a particle is dropped from the top of a very high tower then the distance covered in the fifth second of its fall is?​

Answer 1

Answer:

Explanation:

to find distance covered in 5th second,

u=0 m/s (freely falling body)

a=10m/s

s= u+1/2 a (2t-1)

 =0+1/2*10*(2*5-1)

 = 5*9

 =45m