Question

A particle is dropped from the tower of
height 180 how long it takes to reach the ground what is the velocity when it touches the ground

Answer 1

Explanation:

g =10 m/s^2, s =180 m, u = 0

as per equation of motion

v^2 = u^2 + 2*g*s

v^2 = 0 + 2*10*180 = 3600

taking square root

v = 60 m/s

so the particle will strike with velocity

60 m/s