Question

a particle is dropped from top of a tower during it's motion it covers 9/25 part of height of tower in last 1 sec . find height of tower​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

Let the height of tower be 'h' .

During the last 1 sec it covers 9h/25 height.

we have the equation :

S=ut +1/2at²                (since the body is falling from a height a=g,u=0)

9h/25 = 0 +1/2*10*1*1

9h=5*25

h=125/9=13.89 m

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