Question

A particle is dropped from top of the tower.It is found that it travels 45 m in the last second of its journey.Find out the height of the tower.

Answer 1

Distance travelled in last second
S = u + a(n - 1/2)
45 = 0 + 10(n - 1/2)
n = 4.5 + 0.5
n = 5th second

Total time of flight is 5 seconds

Height of the tower
H = 0.5gt^2
= 0.5 × 10 × 5^2
= 125 m

Height of the tower is 125 m

Answer 2

Answer:

height of tower is 125

Explanation:

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