Question

A particle is dropped under gravity from rest from a height h

Answer 1

The particle dropped from the height, h and its initial velocity, u=0 m/s and its falls under the experience of gravity so the acceleration, a= g (acceleration due to gravity) and its final velocity be v m/s

According to the the third equation of motion,

v^2 =u^2 + 2as

By substituting the given the information,

Then the equation becomes,

v^2 = (0)^2 + 2gh

v^2 = 2gh

or v = under root (2gh)