Question

A particle is executing S.H.M if its amplitude is 2m and time period is 2seconds. Then the
maximum velocity of the particle will be:
a) 6π
b) 4π
C. 2π
D. π

Answer 1

Answer:

$\green{\to V_{max} = 4\pi \: m/s}$

Explanation:

$\circ \:Time \: period = 2 \: sec \\ \\ \circ \: Amplitude = 2 \: m \\ \\ \bold{Maximum \: velocity = \sqrt{ \frac{k}{m} } \times a} \\ \\ \to V_{max} = \sqrt{ \frac{k}{m} } \times A \\ \\ \bold{ \sqrt{ \frac{k}{m} } = T}\\ \\ \to V_{max} =T\times A\\ \\ \to V_{max} = 2 \times 2 \\ \\ \green{\to V_{max} = 4\pi \: m/s}$