A particle is executing S. H.M of amplitude 5cm and period of 2s. Find the speed of the particle at a point where its acceleration is half of its maximum value.
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w=2π/prd. =π rad /s. max acc=w^2A=π^2 *5
it's half is 2.5π^2
also acc=w^2 Asin wt substitute values
π^2 *2.5=π^2 *5*sinwt
thus sin wt=0.5. t=1/3 s
it's half is 2.5π^2
also acc=w^2 Asin wt substitute values
π^2 *2.5=π^2 *5*sinwt
thus sin wt=0.5. t=1/3 s
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