Question

A particle is executing S.H.M. with amplitude
'a' and has maximum velocity'v'. Its speed
at displacement a/2 will be -
(A) 0.866 v
(B) v12
(C) v
(D) 1/4​

Answer 1

Answer:

A

V = w √A^2 - x^2

x = A/2

V = √3Aw/2

V = 0.866Aw

( vmax = Aw )

V = 0.866v