Question

A particle is executing SHM about y = 0 along yaxis. Its position at an instant is given by y = (7 m) sin(¶t)
Its average velocity for a time interval 0 to 0.5 s is
(1) 14 m/s
(2) 7 m/s
(3) 1/7m/s
(4) 28 m/s​

Answer 1

Answer:

hopefully it will help u.any prob feel free to ask

Answer 2

The average velocity for a given time interval 0 to 0.5 s is 14 m/s

Explanation:

$y(t)=7sin(\pi t)$

Substitute t=0

$y_1=7sin(0)=0$

Substitute t=0.5

$y_2=7sin(\pi\times 0.5)=7sin(\pi\times \frac{5}{10})=7sin\frac{\pi}{2}$

$sin\frac{\pi}{2}=1$

$y_2=7$

Average velocity=$\frac{y_2-y_1}{t_2-t_1}$

Substitute $t_1=0,t_2=0.5,y_1=0,y_2=1$

Average velocity, v=$\frac{7-0}{0.5-0}=\frac{7}{0.5}$

Average velocity, v=$14m/s$

Option (1) is true.

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