Physics, asked by felfela983, 11 months ago

A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂, respectively. Its time period is(a) 2\pi \sqrt{\frac{x^{2}_{2}-x^{2}_{1}}{V^{2}_{1}-V^{2}_{2}}}(b) 2\pi \sqrt{\frac{V^{2}_{1}+V^{2}_{2}}{x^{2}_{1}+x^{2}_{2}}}(c) 2\pi \sqrt{\frac{V^{2}_{1}-V^{2}_{2}}{x^{2}_{1}-x^{2}_{2}}}(d) 2\pi \sqrt{\frac{x^{2}_{1}-x^{2}_{2}}{V^{2}_{1}-V^{2}_{2}}}

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Answered by VISHAL7076
0

sorry but it is very difficult to understand

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