Question

A particle is executing SHM of period 4s. Then the time taken by it to move fromthe extreme position to half the amplitude is

Answer 1

Hey dear,

● Answer-

t = 0.67 s

● Explanation-

# Given-

T = 4 s

x = A/2

# Solution-

In SHM, displacement of particle starting from extreme position is given by eqn,

x = Acos(ωt)

A/2 = Acos(ωt)

cos(ωt) = 1/2

Taking cos inverse,

ωt = cosinv(1/2)

2πt/T = π/3

t = T/6

t = 4/6

t = 0.67 s

Therefore, time taken by particle to move from extreme position to half amplitude is 0.67 s.

Hope this helps you...

Answer 2

Answer:

1/3sec

Explanation:

if u take x= a sin (wt)