Question

A particle is executing shm with time period t starting from mean position time taken by it to complete 5/8 oscillation is

Answer 1

Answer:

A particle is executing shm with time period t starting from mean position time taken by it to complete 5/8 oscillation is 7T/12

Explanation:

Let the whole distance which is covered by the particle = 4A.  

 5/8 oscillations means, it has already completed 1/2 oscillation

Therefore total distance will be 2A

also the half way is A/2

A/2 = Asinwt,

w= 2pi/ T

putting the value of w

t= T/12.

Therefore

Total time taken =time to complete previous one half + time to complete A/2

                              = t/2 + t/12 = 7T/12.

Answer 2

Answer: You may use the following shortcut...

Explanation: