Question

A particle is executing simple harmonic
motion in a line 1.0 m long. If the time of
one complete vibration is 1 sec, then the
maximum velocity of the particle is​

Answer 1

Answer:

Maximum acceleration

α=ω

2

y

∴0.5=ω

2

×0.02

or ω

2

=

0.02

0.5

=25

So, ω=5

Now, maximum velocity is

v=aω=0.1×5=0.5m/s