Question

a particle is executing simple harmonic motion that time taken for 3by8th of oscillation from extreme position is x.then the time taken 5by8th oscillation is

Answer 1

Answer:

Explanation:

we know standard formula for harmonic motion is

x1=asin(wt+phi)

x1/a=sin(wt+phi)

extreme means phi = pi/2

x1/a =sin( wt+ pi/2)

x1/a = cos wt

3/8 a /a =cos wt

3/8=cos wx

cos^- (3/8)= wx

cos^-(3/8) / x= w

x2/a=cos wt

5/8=cos (cos^-(3/8) /x *t

5/8=3t/8x

5x/3=t

1.67 x =t

Answer 2

Answer:

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