Question

A particle is executing uniform circular motion with speed 1 cm/s and the
radius of the circular track is 7 cm. Find the magnitude of displacement of it in
11 s.​

Answer 1

Answer:

v=1 cm/s = 10^-2 m/s

r = 7 cm = 7 x 10^-2 m

Explanation:

w= v/r = 1/7 rad/s

d(theta)= 1/7 x dt = 11/7rad =22/7 x2=π/2