Question

A particle is executing uniform circular motion with speed 1 cm/s and the radius of the circular track is 7 cm. Find the magnitude of displacement of it in 11 s.​

Answer 1

Answer:

Here A particle of mass 'm' is executing uniform circular motion 

Here A particle of mass 'm' is executing uniform circular motion Radius r=p=mv

Here A particle of mass 'm' is executing uniform circular motion Radius r=p=mvwhere v is velocity 

Here A particle of mass 'm' is executing uniform circular motion Radius r=p=mvwhere v is velocity So centripetal force = Radial force = rmv2=rmm2v2=rmp2

Answer 2

• v=1 cm/s = 10^-2 m/s r = 7 cm = 7 x 10^-2 m
• v=1 cm/s = 10^-2 m/s r = 7 cm = 7 x 10^-2 mExplanation:
• v=1 cm/s = 10^-2 m/s r = 7 cm = 7 x 10^-2 mExplanation:wv/r = 1/7 rad/s
• v=1 cm/s = 10^-2 m/s r = 7 cm = 7 x 10^-2 mExplanation:wv/r = 1/7 rad/sd(theta)= 1/7 x dt = 11/7rad =22/7 x2=π/2

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