Question

A particle is executing uniform circular motion with speed 1 cm/s and the radius of the circular track is 7 cm. Find the magnitude of displacement of it in 11 s.

give correct answer​

Answer 1

Answer:

9.898cm (or) 10cm

Explanation:

Circumference of the circular track is 2*pi*r = 2*22/7*7= 44cm

Distance travelled by the particle is Speed *time= 11*1 = 11cm i.e.,

exactly one-fourth of circumference.

So, the displacement and distance would be as shown in the figure.

It would form a right angled triangle with the displacement and hence we can use the "Pythagoras theorem for finding displacement.

Displacement from A to B is $\sqrt{7*7 + 7*7} = 7\sqrt{2} =7*1.414 = 9.898$cm