Question

a particle is fired from a point on the ground with speed u making an angle tetha with the horizontal. then ​

Answer 1

The complete question is:

A particle is fired with velocity u making angle θ with the horizontal. What is the magnitude of change in velocity when it is at the highest point?

Answer:

u Sin θ

The particle's speed is u and the particle's speed at the highest point the particle's speed is ucosθ at the time of projection. Thus, the change in speed is:

Δu=u−ucosθ

So, now the initial velocity is,

u =ucosθ i^ +usinθ j^

​

Final velocity:

v =ucosθ i^

Thus, the change in velocity is:

Δ v = u − v = ucosθ i^ +usinθ j^−ucosθ i^ =usinθ j^

⇒∣Δv∣=usinθ

See a similar question here:

What is the formula for finding velocity​

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