Physics, asked by Anonymous, 9 months ago

A particle is fired from ground with velocity u making
an angle with vertical. The magnitude of change in
velocity of the particle when it will hit the ground​

Answers

Answered by jeevan29jamy
2

Answer:

At the time of projection, the particle's speed is u and the particle's speed at the highest point the particle's speed is ucosθ. So, the change in speed is,

Δu=u−ucosθ

Now, the initial velocity is,

u

=ucosθ

i

^

+usinθ

j

^

and the final velocity (at highest point) is,

v

=ucosθ

i

^

Therefore, the change in velocity is,

Δ

v

=

u

v

=ucosθ

i

^

+usinθ

j

^

−ucosθ

i

^

=usinθ

j

^

⇒∣Δ

v

∣=usinθ

Answered by arunakmanju875
1

Answer:

I don't like facebook and I don't have insta and I don't like also tell any other social media

Similar questions