A particle is fired from ground with velocity u making
an angle with vertical. The magnitude of change in
velocity of the particle when it will hit the ground
Answers
Answered by
2
Answer:
At the time of projection, the particle's speed is u and the particle's speed at the highest point the particle's speed is ucosθ. So, the change in speed is,
Δu=u−ucosθ
Now, the initial velocity is,
u
=ucosθ
i
^
+usinθ
j
^
and the final velocity (at highest point) is,
v
=ucosθ
i
^
Therefore, the change in velocity is,
Δ
v
=
u
−
v
=ucosθ
i
^
+usinθ
j
^
−ucosθ
i
^
=usinθ
j
^
⇒∣Δ
v
∣=usinθ
Answered by
1
Answer:
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