Question

A particle is fired horizontally from an inclined plane of inclination 30 degree with horizontal velocity 50 m per second the range measured along the incline is

Answer 1

Heya!!Here is your answer friend ⤵⤵

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⏪The Horizontal Range (R) of a projectile is given by,

Horizontal velocity × time of flight

=
$u \: cos \: a \times \frac{2u \: sin \: a}{g} \\ u {}^{2} ( \frac{cos \: a \: 2 \: sin \: a}{g} ) \\ \\ r = \frac{u {}^{2} sin2a}{g} \\ putting \: the \: values \: \\ r = \frac{50 \times 50 \: sin \: 2 \times 30}{9.8} \\ r = \frac{2500 \times sin60}{9.8} \\ r = \frac{2500 \times \ \frac{ \sqrt{3} }{2} }{9.8} = 1250\sqrt{3} \div 9.8 \\ \\ 220.66$
Hence , the Horizontal range is 220.66m


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