A particle is fired vertically upwards from earth surface and it goes up to a maximum height of 6400 km find the initial speed of the particle??
Answers
Answered by
3
2gs=v^2-u^2
g=9.8m/s^2
s=6400km
=(6400x1000)m
2x9.8x6400x1000=(0)^2-u^2
62719998=u^2
u=√62719998
u=7919.59582.........
g=9.8m/s^2
s=6400km
=(6400x1000)m
2x9.8x6400x1000=(0)^2-u^2
62719998=u^2
u=√62719998
u=7919.59582.........
anu2211:
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I used the equation
then just substituted the values
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Answered by
1
v=0
u=?
s=6400km =6400000m
use the equation v²-u²=2aS and substitute the given values
0²-u²=2 x -9.8 x 6400000
-u² = -125440000
u² = 125440000
u=112000m/s
u=?
s=6400km =6400000m
use the equation v²-u²=2aS and substitute the given values
0²-u²=2 x -9.8 x 6400000
-u² = -125440000
u² = 125440000
u=112000m/s
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