Question

A particle is fired with velocity u making angle theta with the horizontal, what is the change in speed

Answer 1

Answer:

The change in speed is u−u cos θ

Explanation:

According to the problem a particle is thrown with velocity u and making angle θ

Therefore at the time of projection the particle's speed is u

The particle's speed at the highest point is u cos θ

So, the change in speed is,

Δu=u−u cos θ

Hence the answer will be u−u cos θ

Answer 2

Answer:

The change in speed is u−u cos θ

Explanation:

According to the problem a particle is thrown with velocity u and making angle θ

Therefore at the time of projection the particle's speed is u

The particle's speed at the highest point is u cos θ

So, the change in speed is,

Δu=u−u cos θ

Hence the answer will be u−u cos θ