Question

A particle is fired with velocity u making angle with the horizontal. What is the change in velocity when it is at the highest point?​

Answer 1

Answer:

At the time of projection, the particle's speed is u and the particle's speed at the highest point the particle's speed is ucosθ. So, the change in speed is,

Δu=u−ucosθ

Now, the initial velocity is,

u

=ucosθ

i

^

+usinθ

j

^

and the final velocity (at highest point) is,

v

=ucosθ

i

^

Therefore, the change in velocity is,

Δ

v

=

u

−

v

=ucosθ

i

^

+usinθ

j

^

−ucosθ

i

^

=usinθ

j

^

⇒∣Δ

v

∣=usinθ

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