Question

A particle is forming linear SHM its KE is two times its PE at a position 'A' and its
PE is two times its KE at another position B. The ratio of KE at A to KE at B is
1) 1:2
2) 2:1
3) 4 : 1
4) 1:4

please give full solution ​

Answer 1

Answer:

2) 2:1

Explanation:

Solution

TEA=KEA+PEA

But KEA=2PEA,

TEA=KEA+12KEA=32KEA.

Similarly, TEB=KEB+PEB.

But PEB=2KEB

TEB=kEB+2KEB=3KEB.

By the principle of conservation of energy

TEA=TEB,32KEA=3KEB

KEAKEB=2:1