Question

A particle is given an initial speed ‘u' inside a smooth fixed spherical shell of radius r = 1 m such that it is just able to complete the circle. Acceleration of the particle when its velocity is vertical, is

Answer 1

acceleration is 0 because it has just complete the circle so displacemenet become zero

Answer 2

$\huge\bf{Answer:-}$

Let u be the speed.

Let r be the radius.

$u {}^{2} = 5gr \\ v {}^{2} = u {}^{2} - 2gr \\ = 5gr - 2gr \\ = 3gr \\ = a(t) = g \\ = a(c) = v = v \frac{2}{r}$

$a(c) = \frac{v {}^{r} }{r} = \frac{3g {}^{r} }{r} = 3g$

$Acceleration = \sqrt{a(t) {}^{4} } + a {}^{2} (c)$

$= \sqrt{g {}^{2}+ 3g {}^{2} }$

$= \sqrt{g {}^{2} + 3g {}^{2} }$

$= g \sqrt{10}$