Physics, asked by bipinchandra69, 8 months ago

A particle is going parallel to x-axis with constant speed V at a distance 'a' from the axis. Find its
angular velocity about an axis passing the origin O, at the instant when radial vector of the particle
makes angle with the x-axis​

Answers

Answered by nirman95
2

Given:

A particle is going parallel to x-axis with constant speed V at a distance 'a' from the axis.

To find:

Angular velocity when radial vector makes an angle of \theta with x axis.

Calculation:

Perpendicular distance of object from x axis be r ;

 \therefore \:  \dfrac{r}{a}  =  \sin( \theta)

 =  > r = a \sin( \theta)

Now , angular velocity is calculated by the ratio of tangential velocity to the perpendicular distance from axis ;

 \boxed{ \sf{angular \: velocity =  \dfrac{tangential \: v}{perpendicular \: distance} }}

 =  > \sf{ \omega =  \dfrac{v}{r} }

 =  > \sf{ \omega =  \dfrac{v}{a \sin( \theta) } }

So, final answer is:

 \boxed{ \red{\sf{ \omega =  \dfrac{v}{a \sin( \theta) } }}}

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