A particle is having a charge of 2.0*10-4C is placed directly below and at a separation of 10 cm from the bobof a simple pendulum at rest. The mass of the bob is 100g. What charge should the bob be given so that the string becomes loose.
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Explanation:
We have been given the mass which is 100g,charge which is 2×10^-4 and the separation is 10 cm
As string looses force will be equal to mass × gravity
By equating force equal to mass × gravity
F×mg
kq1×q2/r^2=10^-1×9.8
By keeping all the values
q2=10^-1×9.8×10^-2/2×10^-4×9×10^9
q2=~5.4×10^-9
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