Question

A particle is in motion and is accelerated functional form of velocity is V(t) is equal to 20t - 5t^2 metre per second. find instantaneous acceleration at t= 1,2,3 and 5

Answer 1

Answer:

Explanation:

since we have to find the instantaneous acceleration

=>we have to differentiate the functional form of velocity

=>20t-5t^2=d/dx20t-5t^2

=20-10t

so this is the instantaneous functional form of acceleration

now put the values of t accordingly,

t=1,20-10(1)=10m/s^2

t=2,20-10(2)=0m/s^2

t=3,20-10(3)= -10m/s^2

t=5,20-10(5)= -30m/s^2

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