Question

A particle is in simple harmonic motion with period T. At time t = 0 it is at the equilibrium point. Of the following times, at which time is it furthest from the equilibrium point?

Answer 1

Answer:

0.7T

Explanation:

Answer 2

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Options:

A. 0.5T

B. 0.75T

C. T

D. 1.4T

E. 1.5T

Concept:

• Simple harmonic motion

Given:

• at time t = 0, the particle is at the equilibirum point

Find:

• The point of time at which the particle is furthest from the equilibrium

Solution:

x = A sin wt

where x is the displacement, A is the amplitude of the SHM, w is the angular velocity of the particle and t is the time

The point which is furthest from the equilibrium point is at a distance A from the equilibrium point.

x = 0 when time T passes (one oscillation is complete)

x = A when time T/4 passes (a quarter of the oscillation is complete)

x = -A when time 3T/4 = 0.75T passes

The correct option is 0.75T.

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