Question

A particle is in simple harmonic motion with period t at time t is equal to zero it is at equilibrium point​

Answer 1

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Answer 2

Answer:

Position of particle excecuting SHM.

x=Asinwt

Its velocity function is v=

dt

dx

=Aωcoswt

Kinectic energy K.E. =

2

1

mv

2

=

2

1

mA

2

ω

2

cos

2

ωt

⇒K.E.∝cos

2

ωt

But at t=

4

T

cos(ω

4

r

)=0⇒K.E=0

at t=

2

T

cos(ω

2

r

)=−1⇒K.E is maximum

at t=T cos(ωT)=1⇒K.E is maximum

Explanation:

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