A particle is initially at rest and starts with an acceleration of 2 metre per second square then find the velocity of the particle at t is equals to 2 second find by velocity =dislpacement /time method
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Let t be the time in seconds from the beginning of the motion of a particle. If the particle has a velocity of 4 m/s initially (at t=0) and has a constant acceleration of 2 m/s2, find the velocity of the particle:
when t=1
when t=2
after t seconds.
Draw the velocity–time graph for the motion.
Solution
When t=1, the velocity of the particle is 4+2=6 m/s.
When t=2, the velocity of the particle is 4+2×2=8 m/s.
After t seconds, the velocity of the particle is 4+2t m/s.
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