Question

A particle is kept at rest at distance 3R (R is radius of
earth) from the centre of earth. The minimum speed
with which it should be projected so that it escapes
from the earth's gravitational field is...



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Answer 1

Answer:

√GM / 3R

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Answer 2

Given:

Distance of the particle from the center of the Earth = 3R

To find:

The minimum speed  with which it should be projected so that it escapes  from the earth's gravitational field.

Solution:

We know that the escape velocity is $v=\sqrt{\frac{2GM}{R} }$

Where R is the distance of the particle from centre of the Earth.

Here R = 3R, so:

$v=\sqrt{\frac{2GM}{3R} }$

Therefore the correct option is (a).