A particle is located midway between two point masses each of mass M kept at a separation 2d. The escape speed of the particle is (neglect the effect of any other gravitational effect)
1) sqrt (2GM/d)
2) 2 sqrt (GM/d)
3) sqrt (3GM/d)
4) sqrt (GM/2d)
Answers
Answered by
10
Answer:
(2) 2√(GM/d)
Explanation:
according to energy conservation,
to escape, total energy of the particle = 0
Potential energy + kinetic energy = 0
-GMm/d - GMm/d + 1/2 m v^2 = 0
=> v^2 = 4GM/d
=> v = 2 √(GM/d)
aabhamisra:
Thank you...
:)
Similar questions