Question

A PARTICLE IS MOOVING IN A CIRCULAR PATH OF RADIUS R , THE DISPLACEMENT AFTER HALF a circular WOULD BE. what
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Answer 1

Answer:

the displacement would be 2R.

Answer 2

Explanation:

Correct Question : copies trying

The numerator of the fraction is 3 less than the denominator. If 1 is added to both its numerator and denominator it becomes 1/2 . Find the fraction.

Given :

Numerator of a fraction is 3 less than its Denominator .

If 1 is added to both its numerator and denominator it becomes 1/2 .

To Find :

Original Fraction .

Solution :

$\longmapsto\tt{Let\:Denominator\:be=x}$

As Given that Numerator of a fraction is 3 less than its Denominator . So ,

$\longmapsto\tt{Numerator=x-3}$

Now ,

If 1 is added to both its numerator and denominator it becomes 1/2 .

$\longmapsto\tt{Numerator=x-3+1=x-2}$

$\longmapsto\tt{Denominator=x+1}$

A.T.Q :

$\longmapsto\tt{\dfrac{x-2}{x+1}=\dfrac{1}{2}}$

$\longmapsto\tt{2(x-2)=1(x+1)}$

$\longmapsto\tt{2x-4=1x+1}$

$\longmapsto\tt{2x-1x=1+4}$

$\longmapsto\tt\bf{x=5}$

Value of x is 5 ..

Therefore :

$\longmapsto\tt{Numerator=5-3}$

$\longmapsto\tt\bf{2}$

$\longmapsto\tt\bf{Denominator=5}$

So , The Fraction is 2/5 .