Physics, asked by varshareddymettu26, 11 months ago

A particle is moved along a path
AB- BC - CD- DE - EF - FA
as shown in figure, in presence of a force
F=(Qyi + 200}) N. Where 'x' and
'y' are in metre and alpha=-1 Nm-1. The
work done on the particle by this force
when the particle move from AB - BC
path will be............. joule.​

Answers

Answered by reddyvenkat1995
1

Answer:

https://www.sarthaks.com/402738/particle-moved-along-path-cd-de-ef-as-shown-in-figure-in-presence-of-force-yi-2xj-where-and

Explanation:

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