Question

A particle is moving along a circle of radius 1.5m. If centripetal acceleration of particle is 6mspower-2,then angular velocity of that particle is? ​

Answer 1

Answer:

so angular velocity ω=2 rad/sec.

Explanation:

Since it is given that a particle is moving along a circle of radius 1.5m and centripetal acceleration of particle is 6m/s^2.

r=1.5m , a=6m/s^2.

we know that centripetal acceleration is given by

$a=\frac{v^{2} }{r}$

$6=\frac{v^{2} }{1.5}$

after cross multiply we get

$\sqrt{6\times1.5} =v$

therefore linear velocity v=3m/s

we know the relationship between linear velocity and angular velocity

v=rω where ω=angular velocity

3=1.5ω

so angular velocity ω=2 rad/sec.