Physics, asked by malakardebarati, 1 year ago

A particle is moving along a circle such that it completes one revolution in 40 sec.in 2 min 20 sec the ratio of |displacement /distance| is

Answers

Answered by Bebrainly2
2
hello there!!!!

Time taken to cover one revolution of the circle = 40 sec

Time taken to cover two revolution = 2× 40 = 80 sec or 2min 20 sec

Distance covered in 2m 20sec = 2× 2πr = 4πr m
Displacement covered in two revolution ie in 2m 20 sec = 2×0 =0 m

Ratio of Displacement /distance is 0
As , Displacement / distance = 0 / 4πr =0

hope it helps you......

JunaidMirza: 80 seconds is not 2min 20sec

1min = 60s
2min = 120s

2min 20s = 120s + 20s = 140s
Answered by JunaidMirza
9
One revolution in 40 seconds
Number of revolution in 140 seconds = 140/40 = 3.5

Distance travelled in 3.5 revolutions = 3.5 * 2 pi*r = 3.5 * 2 * 22/7 * r = 22r
Displacement in 3.5 revolutions = 3*0 + 2r = 2r


Ratio of displacement to distance = 2r / 22r = 1/11 = 1 : 11
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