A particle is moving along a circle such that it completes one revolution in 40 sec.in 2 min 20 sec the ratio of |displacement /distance| is
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2
hello there!!!!
Time taken to cover one revolution of the circle = 40 sec
Time taken to cover two revolution = 2× 40 = 80 sec or 2min 20 sec
Distance covered in 2m 20sec = 2× 2πr = 4πr m
Displacement covered in two revolution ie in 2m 20 sec = 2×0 =0 m
Ratio of Displacement /distance is 0
As , Displacement / distance = 0 / 4πr =0
hope it helps you......
Time taken to cover one revolution of the circle = 40 sec
Time taken to cover two revolution = 2× 40 = 80 sec or 2min 20 sec
Distance covered in 2m 20sec = 2× 2πr = 4πr m
Displacement covered in two revolution ie in 2m 20 sec = 2×0 =0 m
Ratio of Displacement /distance is 0
As , Displacement / distance = 0 / 4πr =0
hope it helps you......
Answered by
9
One revolution in 40 seconds
Number of revolution in 140 seconds = 140/40 = 3.5
Distance travelled in 3.5 revolutions = 3.5 * 2 pi*r = 3.5 * 2 * 22/7 * r = 22r
Displacement in 3.5 revolutions = 3*0 + 2r = 2r
Ratio of displacement to distance = 2r / 22r = 1/11 = 1 : 11
Number of revolution in 140 seconds = 140/40 = 3.5
Distance travelled in 3.5 revolutions = 3.5 * 2 pi*r = 3.5 * 2 * 22/7 * r = 22r
Displacement in 3.5 revolutions = 3*0 + 2r = 2r
Ratio of displacement to distance = 2r / 22r = 1/11 = 1 : 11
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1min = 60s
2min = 120s
2min 20s = 120s + 20s = 140s